Test your knowledge on Algebraic Equations level 2
How can you rearrange 4x + 2y = 6 into the form y = mx + c?
Subtract 4x from each side to isolate the y term: 2y = -4x + 6.
Divide both sides by 2 to get y = -2x + 3.
Solve 2(x^2) = 162
2(x^2) = 162. Dividing both sides by 2 gives x^2 = 81.
Square root both sides gives x = ± 9.
Solve 3(x^2) - 5 = 43
3(x^2)- 5 = 43. Add 5 to each side giving 3x2 = 48.
Divide each side by 3 to get x2 = 16, and square root to find x.
x = ± 4.
Solve x^2 - 5x - 14 = 0
x^2- 5x - 14 = 0 factorises to (x - 7)(x + 2) = 0. To solve, put each bracket equal to zero. x - 7 = 0 gives x = 7 and x + 2 = 0 gives x = -2. The solutions are x = 7 and x = -2.
Solve (x^2) + 10x + 6 = 0
x^2 + 10x + 6 = 0. Completing the square gives (x+10/2^)2−(10/2)^2+6=0.
This simplifies to (x + 5)^2 - 52 + 6 = 0.
(x + 5)^2 - 25 + 6 = 0.
(x + 5)^2 - 19 = 0.
To solve, add 19 to each side giving (x + 5)^2 = 19.
Square root each side, giving x+5=± suq(19)
To find x, subtract 5 from each side, giving the final answer of
x=−5± suq (19)
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